David had 20% more beads than Ahmad. David gave 25% of his beads to Ahmad. Ahmad in return gave 40% of his beads to David. In the end, Ahmad had 704 less beads than David. How many beads did Ahmad have in the end?
| |
David |
Ahmad |
| Before |
120% |
100% |
| Change 1 |
- 30% |
+ 30% |
| After 1 |
90% |
130% |
| Change 2 |
+ 52% |
- 52% |
| After 2 |
142% |
78% |
Number of beads that David had at first in percent
= 100% + 20%
= 120%
Number of beads that David gave to Ahmad in percent
= 25% x 120%
=
25100 x 120%
= 30%
Number of beads that Ahmad gave to David in percent
= 40% x 130%
=
40100 x 130%
= 52%
Number of less beads that Ahmad had than David in the end
= 142% - 78%
= 64%
64% → 704
1% → 704 ÷ 64 = 11
Number of beads that Ahmad had in the end
= 78%
= 78 x 11
= 1320
Answer(s): 1320
