Simon had 50% more marbles than Cody. Simon gave 30% of his marbles to Cody. Cody in return gave 20% of his marbles to Simon. In the end, Cody had 90 less marbles than Simon. How many marbles did Cody have in the end?
| |
Simon |
Cody |
| Before |
150% |
100% |
| Change 1 |
- 45% |
+ 45% |
| After 1 |
105% |
145% |
| Change 2 |
+ 29% |
- 29% |
| After 2 |
134% |
116% |
Number of marbles that Simon had at first in percent
= 100% + 50%
= 150%
Number of marbles that Simon gave to Cody in percent
= 30% x 150%
=
30100 x 150%
= 45%
Number of marbles that Cody gave to Simon in percent
= 20% x 145%
=
20100 x 145%
= 29%
Number of less marbles that Cody had than Simon in the end
= 134% - 116%
= 18%
18% → 90
1% → 90 ÷ 18 = 5
Number of marbles that Cody had in the end
= 116%
= 116 x 5
= 750
Answer(s): 750
