Sean had 50% more balls than Ryan. Sean gave 20% of his balls to Ryan. Ryan in return gave 50% of his balls to Sean. In the end, Ryan had 1080 less balls than Sean. How many balls did Sean have at first?
| |
Sean |
Ryan |
| Before |
150% |
100% |
| Change 1 |
- 30% |
+ 30% |
| After 1 |
120% |
130% |
| Change 2 |
+ 65% |
- 65% |
| After 2 |
185% |
65% |
Number of balls that Sean had at first in percent
= 100% + 50%
= 150%
Number of balls that Sean gave to Ryan in percent
= 20% x 150%
=
20100 x 150%
= 30%
Number of balls that Ryan gave to Sean in percent
= 50% x 130%
=
50100 x 130%
= 65%
Number of less balls that Ryan had than Sean in the end
= 185% - 65%
= 120%
120% → 1080
1% → 1080 ÷ 120 = 9
Number of balls that Sean had at first
= 150%
= 150 x 9
= 1350
Answer(s): 1350
