Albert had 10% more balls than Justin. Albert gave 20% of his balls to Justin. Justin in return gave 50% of his balls to Albert. In the end, Justin had 440 less balls than Albert. How many balls did Justin have in the end?
| |
Albert |
Justin |
| Before |
110% |
100% |
| Change 1 |
- 22% |
+ 22% |
| After 1 |
88% |
122% |
| Change 2 |
+ 61% |
- 61% |
| After 2 |
149% |
61% |
Number of balls that Albert had at first in percent
= 100% + 10%
= 110%
Number of balls that Albert gave to Justin in percent
= 20% x 110%
=
20100 x 110%
= 22%
Number of balls that Justin gave to Albert in percent
= 50% x 122%
=
50100 x 122%
= 61%
Number of less balls that Justin had than Albert in the end
= 149% - 61%
= 88%
88% → 440
1% → 440 ÷ 88 = 5
Number of balls that Justin had in the end
= 61%
= 61 x 5
= 550
Answer(s): 550
