Nick had 50% more balls than Reggie. Nick gave 30% of his balls to Reggie. Reggie in return gave 20% of his balls to Nick. In the end, Reggie had 36 less balls than Nick. How many balls did Reggie have in the end?
| |
Nick |
Reggie |
| Before |
150% |
100% |
| Change 1 |
- 45% |
+ 45% |
| After 1 |
105% |
145% |
| Change 2 |
+ 29% |
- 29% |
| After 2 |
134% |
116% |
Number of balls that Nick had at first in percent
= 100% + 50%
= 150%
Number of balls that Nick gave to Reggie in percent
= 30% x 150%
=
30100 x 150%
= 45%
Number of balls that Reggie gave to Nick in percent
= 20% x 145%
=
20100 x 145%
= 29%
Number of less balls that Reggie had than Nick in the end
= 134% - 116%
= 18%
18% → 36
1% → 36 ÷ 18 = 2
Number of balls that Reggie had in the end
= 116%
= 116 x 2
= 300
Answer(s): 300
