Nick had 50% more balls than Luke. Nick gave 20% of his balls to Luke. Luke in return gave 40% of his balls to Nick. In the end, Luke had 470 less balls than Nick. How many balls did Nick have at first?
| |
Nick |
Luke |
| Before |
150% |
100% |
| Change 1 |
- 30% |
+ 30% |
| After 1 |
120% |
130% |
| Change 2 |
+ 52% |
- 52% |
| After 2 |
172% |
78% |
Number of balls that Nick had at first in percent
= 100% + 50%
= 150%
Number of balls that Nick gave to Luke in percent
= 20% x 150%
=
20100 x 150%
= 30%
Number of balls that Luke gave to Nick in percent
= 40% x 130%
=
40100 x 130%
= 52%
Number of less balls that Luke had than Nick in the end
= 172% - 78%
= 94%
94% → 470
1% → 470 ÷ 94 = 5
Number of balls that Nick had at first
= 150%
= 150 x 5
= 750
Answer(s): 750
