Oliver had 10% more balls than Perry. Oliver gave 20% of his balls to Perry. Perry in return gave 50% of his balls to Oliver. In the end, Perry had 264 less balls than Oliver. How many balls did Perry have in the end?
| |
Oliver |
Perry |
| Before |
110% |
100% |
| Change 1 |
- 22% |
+ 22% |
| After 1 |
88% |
122% |
| Change 2 |
+ 61% |
- 61% |
| After 2 |
149% |
61% |
Number of balls that Oliver had at first in percent
= 100% + 10%
= 110%
Number of balls that Oliver gave to Perry in percent
= 20% x 110%
=
20100 x 110%
= 22%
Number of balls that Perry gave to Oliver in percent
= 50% x 122%
=
50100 x 122%
= 61%
Number of less balls that Perry had than Oliver in the end
= 149% - 61%
= 88%
88% → 264
1% → 264 ÷ 88 = 3
Number of balls that Perry had in the end
= 61%
= 61 x 3
= 330
Answer(s): 330
