Ian had 50% more balls than Albert. Ian gave 10% of his balls to Albert. Albert in return gave 20% of his balls to Ian. In the end, Albert had 132 less balls than Ian. How many balls did Albert have in the end?
| |
Ian |
Albert |
| Before |
150% |
100% |
| Change 1 |
- 15% |
+ 15% |
| After 1 |
135% |
115% |
| Change 2 |
+ 23% |
- 23% |
| After 2 |
158% |
92% |
Number of balls that Ian had at first in percent
= 100% + 50%
= 150%
Number of balls that Ian gave to Albert in percent
= 10% x 150%
=
10100 x 150%
= 15%
Number of balls that Albert gave to Ian in percent
= 20% x 115%
=
20100 x 115%
= 23%
Number of less balls that Albert had than Ian in the end
= 158% - 92%
= 66%
66% → 132
1% → 132 ÷ 66 = 2
Number of balls that Albert had in the end
= 92%
= 92 x 2
= 300
Answer(s): 300
