Nick had 10% more balls than Gabriel. Nick gave 20% of his balls to Gabriel. Gabriel in return gave 50% of his balls to Nick. In the end, Gabriel had 792 less balls than Nick. How many balls did Nick have at first?
| |
Nick |
Gabriel |
| Before |
110% |
100% |
| Change 1 |
- 22% |
+ 22% |
| After 1 |
88% |
122% |
| Change 2 |
+ 61% |
- 61% |
| After 2 |
149% |
61% |
Number of balls that Nick had at first in percent
= 100% + 10%
= 110%
Number of balls that Nick gave to Gabriel in percent
= 20% x 110%
=
20100 x 110%
= 22%
Number of balls that Gabriel gave to Nick in percent
= 50% x 122%
=
50100 x 122%
= 61%
Number of less balls that Gabriel had than Nick in the end
= 149% - 61%
= 88%
88% → 792
1% → 792 ÷ 88 = 9
Number of balls that Nick had at first
= 110%
= 110 x 9
= 990
Answer(s): 990
