Julian had 20% more balls than David. Julian gave 10% of his balls to David. David in return gave 25% of his balls to Julian. In the end, David had 364 less balls than Julian. How many balls did Julian have at first?
| |
Julian |
David |
| Before |
120% |
100% |
| Change 1 |
- 12% |
+ 12% |
| After 1 |
108% |
112% |
| Change 2 |
+ 28% |
- 28% |
| After 2 |
136% |
84% |
Number of balls that Julian had at first in percent
= 100% + 20%
= 120%
Number of balls that Julian gave to David in percent
= 10% x 120%
=
10100 x 120%
= 12%
Number of balls that David gave to Julian in percent
= 25% x 112%
=
25100 x 112%
= 28%
Number of less balls that David had than Julian in the end
= 136% - 84%
= 52%
52% → 364
1% → 364 ÷ 52 = 7
Number of balls that Julian had at first
= 120%
= 120 x 7
= 840
Answer(s): 840
