Albert had 40% more beads than Lee. Albert gave 25% of his beads to Lee. Lee in return gave 40% of his beads to Albert. In the end, Lee had 234 less beads than Albert. How many beads did Lee have in the end?
| |
Albert |
Lee |
| Before |
140% |
100% |
| Change 1 |
- 35% |
+ 35% |
| After 1 |
105% |
135% |
| Change 2 |
+ 54% |
- 54% |
| After 2 |
159% |
81% |
Number of beads that Albert had at first in percent
= 100% + 40%
= 140%
Number of beads that Albert gave to Lee in percent
= 25% x 140%
=
25100 x 140%
= 35%
Number of beads that Lee gave to Albert in percent
= 40% x 135%
=
40100 x 135%
= 54%
Number of less beads that Lee had than Albert in the end
= 159% - 81%
= 78%
78% → 234
1% → 234 ÷ 78 = 3
Number of beads that Lee had in the end
= 81%
= 81 x 3
= 420
Answer(s): 420
