Bryan had 50% more balls than David. Bryan gave 30% of his balls to David. David in return gave 40% of his balls to Bryan. In the end, David had 228 less balls than Bryan. How many balls did David have in the end?
| |
Bryan |
David |
| Before |
150% |
100% |
| Change 1 |
- 45% |
+ 45% |
| After 1 |
105% |
145% |
| Change 2 |
+ 58% |
- 58% |
| After 2 |
163% |
87% |
Number of balls that Bryan had at first in percent
= 100% + 50%
= 150%
Number of balls that Bryan gave to David in percent
= 30% x 150%
=
30100 x 150%
= 45%
Number of balls that David gave to Bryan in percent
= 40% x 145%
=
40100 x 145%
= 58%
Number of less balls that David had than Bryan in the end
= 163% - 87%
= 76%
76% → 228
1% → 228 ÷ 76 = 3
Number of balls that David had in the end
= 87%
= 87 x 3
= 450
Answer(s): 450
