Howard had 40% more balls than Michael. Howard gave 20% of his balls to Michael. Michael in return gave 25% of his balls to Howard. In the end, Michael had 288 less balls than Howard. How many balls did Howard have at first?
| |
Howard |
Michael |
| Before |
140% |
100% |
| Change 1 |
- 28% |
+ 28% |
| After 1 |
112% |
128% |
| Change 2 |
+ 32% |
- 32% |
| After 2 |
144% |
96% |
Number of balls that Howard had at first in percent
= 100% + 40%
= 140%
Number of balls that Howard gave to Michael in percent
= 20% x 140%
=
20100 x 140%
= 28%
Number of balls that Michael gave to Howard in percent
= 25% x 128%
=
25100 x 128%
= 32%
Number of less balls that Michael had than Howard in the end
= 144% - 96%
= 48%
48% → 288
1% → 288 ÷ 48 = 6
Number of balls that Howard had at first
= 140%
= 140 x 6
= 840
Answer(s): 840
