Elijah had 20% more balls than Nick. Elijah gave 25% of his balls to Nick. Nick in return gave 40% of his balls to Elijah. In the end, Nick had 192 less balls than Elijah. How many balls did Nick have in the end?
| |
Elijah |
Nick |
| Before |
120% |
100% |
| Change 1 |
- 30% |
+ 30% |
| After 1 |
90% |
130% |
| Change 2 |
+ 52% |
- 52% |
| After 2 |
142% |
78% |
Number of balls that Elijah had at first in percent
= 100% + 20%
= 120%
Number of balls that Elijah gave to Nick in percent
= 25% x 120%
=
25100 x 120%
= 30%
Number of balls that Nick gave to Elijah in percent
= 40% x 130%
=
40100 x 130%
= 52%
Number of less balls that Nick had than Elijah in the end
= 142% - 78%
= 64%
64% → 192
1% → 192 ÷ 64 = 3
Number of balls that Nick had in the end
= 78%
= 78 x 3
= 360
Answer(s): 360
