Paul had 10% more beads than Oscar. Paul gave 20% of his beads to Oscar. Oscar in return gave 50% of his beads to Paul. In the end, Oscar had 528 less beads than Paul. How many beads did Paul have at first?
| |
Paul |
Oscar |
| Before |
110% |
100% |
| Change 1 |
- 22% |
+ 22% |
| After 1 |
88% |
122% |
| Change 2 |
+ 61% |
- 61% |
| After 2 |
149% |
61% |
Number of beads that Paul had at first in percent
= 100% + 10%
= 110%
Number of beads that Paul gave to Oscar in percent
= 20% x 110%
=
20100 x 110%
= 22%
Number of beads that Oscar gave to Paul in percent
= 50% x 122%
=
50100 x 122%
= 61%
Number of less beads that Oscar had than Paul in the end
= 149% - 61%
= 88%
88% → 528
1% → 528 ÷ 88 = 6
Number of beads that Paul had at first
= 110%
= 110 x 6
= 660
Answer(s): 660
