Min's father is 8 times as old as her. Min will be 16 years old in 12 years' time. In how many years' time will Min's age be 60% that of her father's?
| |
Min's father |
Min |
Difference |
Before
(now) |
8x2 =
16 u |
1x2 =
2 u |
7x2 =
14 u |
| Change 1 |
+ 12 |
+ 12 |
|
| After 1 |
|
16 |
|
| Change 2 |
+ ? |
+ ? |
|
| After 2 |
5x7 =
35 u |
3x7 =
21 u |
2x7 =
14 u |
60% =
60100 =
35 Min's father : Min = 5 : 3
The difference in age between Min's father and Min always remains the same. Make the difference in age between Min's father and Min the same. LCM of 7 and 2 is 14.
2 u + 12 = 16
2 u = 16 - 12
2 u = 4
1 u = 4 ÷ 2 = 2
Number of years' time when Min's age will be 60% that of her father's
= 35 u - 44
= 35 x 2 - 44
= 70 - 44
= 26
Answer(s): 26
