Hilda's auntie is 4 times as old as her. Hilda will be 10 years old in 2 years' time. In how many years' time will Hilda's age be 60% that of her auntie's?
| |
Hilda's auntie |
Hilda |
Difference |
Before
(now) |
4x2 =
8 u |
1x2 =
2 u |
3x2 =
6 u |
| Change 1 |
+ 2 |
+ 2 |
|
| After 1 |
|
10 |
|
| Change 2 |
+ ? |
+ ? |
|
| After 2 |
5x3 =
15 u |
3x3 =
9 u |
2x3 =
6 u |
60% =
60100 =
35 Hilda's auntie : Hilda = 5 : 3
The difference in age between Hilda's auntie and Hilda always remains the same. Make the difference in age between Hilda's auntie and Hilda the same. LCM of 3 and 2 is 6.
2 u + 2 = 10
2 u = 10 - 2
2 u = 8
1 u = 8 ÷ 2 = 4
Number of years' time when Hilda's age will be 60% that of her auntie's
= 15 u - 34
= 15 x 4 - 34
= 60 - 34
= 26
Answer(s): 26
