Kimberly's auntie is 6 times as old as her. Kimberly will be 10 years old in 4 years' time. In how many years' time will Kimberly's age be 60% that of her auntie's?
| |
Kimberly's auntie |
Kimberly |
Difference |
Before
(now) |
6x2 =
12 u |
1x2 =
2 u |
5x2 =
10 u |
| Change 1 |
+ 4 |
+ 4 |
|
| After 1 |
|
10 |
|
| Change 2 |
+ ? |
+ ? |
|
| After 2 |
5x5 =
25 u |
3x5 =
15 u |
2x5 =
10 u |
60% =
60100 =
35 Kimberly's auntie : Kimberly = 5 : 3
The difference in age between Kimberly's auntie and Kimberly always remains the same. Make the difference in age between Kimberly's auntie and Kimberly the same. LCM of 5 and 2 is 10.
2 u + 4 = 10
2 u = 10 - 4
2 u = 6
1 u = 6 ÷ 2 = 3
Number of years' time when Kimberly's age will be 60% that of her auntie's
= 25 u - 40
= 25 x 3 - 40
= 75 - 40
= 35
Answer(s): 35
