Gabriel's father is 4 times as old as him. His father will be 44 years old in 12 years' time. In how many years' time will Gabriel's age be 60% that of his father's?
| |
Gabriel's father |
Gabriel |
Difference |
Before
(now) |
4x2 =
8 u |
1x2 =
2 u |
3x2 =
6 u |
| Change 1 |
+ 12 |
+ 12 |
|
| After 1 |
44 |
|
|
| Change 2 |
+ ? |
+ ? |
|
| After 2 |
5x3 =
15 u |
3x3 =
9 u |
2x3 =
6 u |
60% =
60100 =
35 Gabriel's father : Gabriel = 5 : 3
The difference in age between Gabriel's father and Gabriel always remains the same. Make the difference in age between Gabriel's father and Gabriel the same. LCM of 3 and 2 is 6.
8 u + 12 = 44
8 u = 44 - 12
8 u = 32
1 u = 32 ÷ 8 = 4
Number of years' time when Gabriel's age will be 60% that of his father's
= 15 u - 44
= 15 x 4 - 44
= 60 - 44
= 16
Answer(s): 16
