Cole's uncle is 7 times as old as him. His uncle will be 38 years old in 10 years' time. In how many years' time will Cole's age be 60% that of his uncle's?
| |
Cole's uncle |
Cole |
Difference |
Before
(now) |
7x1 =
7 u |
1x1 =
1 u |
6x1 =
6 u |
| Change 1 |
+ 10 |
+ 10 |
|
| After 1 |
38 |
|
|
| Change 2 |
+ ? |
+ ? |
|
| After 2 |
5x3 =
15 u |
3x3 =
9 u |
2x3 =
6 u |
60% =
60100 =
35 Cole's uncle : Cole = 5 : 3
The difference in age between Cole's uncle and Cole always remains the same. Make the difference in age between Cole's uncle and Cole the same. LCM of 6 and 2 is 6.
7 u + 10 = 38
7 u = 38 - 10
7 u = 28
1 u = 28 ÷ 7 = 4
Number of years' time when Cole's age will be 60% that of his uncle's
= 15 u - 38
= 15 x 4 - 38
= 60 - 38
= 22
Answer(s): 22
