Xavier's auntie is 4 times as old as him. His auntie will be 36 years old in 12 years' time. In how many years' time will Xavier's age be 60% that of his auntie's?
| |
Xavier's auntie |
Xavier |
Difference |
Before
(now) |
4x2 =
8 u |
1x2 =
2 u |
3x2 =
6 u |
| Change 1 |
+ 12 |
+ 12 |
|
| After 1 |
36 |
|
|
| Change 2 |
+ ? |
+ ? |
|
| After 2 |
5x3 =
15 u |
3x3 =
9 u |
2x3 =
6 u |
60% =
60100 =
35 Xavier's auntie : Xavier = 5 : 3
The difference in age between Xavier's auntie and Xavier always remains the same. Make the difference in age between Xavier's auntie and Xavier the same. LCM of 3 and 2 is 6.
8 u + 12 = 36
8 u = 36 - 12
8 u = 24
1 u = 24 ÷ 8 = 3
Number of years' time when Xavier's age will be 60% that of his auntie's
= 15 u - 36
= 15 x 3 - 36
= 45 - 36
= 9
Answer(s): 9
