Xavier's mother is 8 times as old as him. His mother will be 37 years old in 5 years' time. In how many years' time will Xavier's age be 60% that of his mother's?
| |
Xavier's mother |
Xavier |
Difference |
Before
(now) |
8x2 =
16 u |
1x2 =
2 u |
7x2 =
14 u |
| Change 1 |
+ 5 |
+ 5 |
|
| After 1 |
37 |
|
|
| Change 2 |
+ ? |
+ ? |
|
| After 2 |
5x7 =
35 u |
3x7 =
21 u |
2x7 =
14 u |
60% =
60100 =
35 Xavier's mother : Xavier = 5 : 3
The difference in age between Xavier's mother and Xavier always remains the same. Make the difference in age between Xavier's mother and Xavier the same. LCM of 7 and 2 is 14.
16 u + 5 = 37
16 u = 37 - 5
16 u = 32
1 u = 32 ÷ 16 = 2
Number of years' time when Xavier's age will be 60% that of his mother's
= 35 u - 37
= 35 x 2 - 37
= 70 - 37
= 33
Answer(s): 33
