Fabian's mother is 6 times as old as him. His mother will be 46 years old in 10 years' time. In how many years' time will Fabian's age be 60% that of his mother's?
| |
Fabian's mother |
Fabian |
Difference |
Before
(now) |
6x2 =
12 u |
1x2 =
2 u |
5x2 =
10 u |
| Change 1 |
+ 10 |
+ 10 |
|
| After 1 |
46 |
|
|
| Change 2 |
+ ? |
+ ? |
|
| After 2 |
5x5 =
25 u |
3x5 =
15 u |
2x5 =
10 u |
60% =
60100 =
35 Fabian's mother : Fabian = 5 : 3
The difference in age between Fabian's mother and Fabian always remains the same. Make the difference in age between Fabian's mother and Fabian the same. LCM of 5 and 2 is 10.
12 u + 10 = 46
12 u = 46 - 10
12 u = 36
1 u = 36 ÷ 12 = 3
Number of years' time when Fabian's age will be 60% that of his mother's
= 25 u - 46
= 25 x 3 - 46
= 75 - 46
= 29
Answer(s): 29
