Abi's auntie is 3 times as old as her. Abi will be 14 years old in 2 years' time. In how many years' time will Abi's age be 70% that of her auntie's?
|
Abi's auntie |
Abi |
Difference |
Before (now) |
3x3 = 9 u |
1x3 = 3 u |
2x3 = 6 u |
Change 1 |
+ 2 |
+ 2 |
|
After 1 |
|
14 |
|
Change 2 |
+ ? |
+ ? |
|
After 2 |
10x2 = 20 u |
7x2 = 14 u |
3x2 = 6 u |
70% =
70100 =
710 Abi's auntie : Abi = 10 : 7
The difference in age between Abi's auntie and Abi always remains the same. Make the difference in age between Abi's auntie and Abi the same. LCM of 2 and 3 is 6.
3 u + 2 = 14
3 u = 14 - 2
3 u = 12
1 u = 12 ÷ 3 = 4
Number of years' time when Abi's age will be 70% that of her auntie's
= 20 u - 38
= 20 x 4 - 38
= 80 - 38
= 42
Answer(s): 42