10% of Luis's savings was $6 more than 40% of Lee's savings. After Luis spent
14 of his savings and Lee spent 40% of his savings, Luis had $225 more than Lee. How much was Luis's saving at first?
|
Lee |
Luis |
Before |
5 u |
20 u + 60 |
Change |
- 2 u |
- 5 u - 15 |
After |
3 u |
15 u + 45 |
Comparing Lee and Luis in the end |
|
225 more |
10% =
10100 =
110 40% =
40100 =
25 110 Luis =
25 Lee + 6
Make the numerators the same. LCM of 1 and 2 is 2.
1x210x2 Luis =
2x15x1 Lee + 6
220 Luis =
25 Lee + 6
Simplify the fractions.
120 Luis =
15 Lee + 3
Let
15 Lee be
1 u.
Lee's savings at first = 5 u
120 Luis =
15 Lee + 3
Let
120 Luis be
1 u + 3.
Luis's savings at first
= 20 x (1 u + 3)
= 20 u + 60
Savings that Lee spent
= 40% x 5 u
=
40100 x 5 u
= 2 u
Savings that Luis spent
=
14 x (20 u + 60)
= 5 u + 15
Luis had $225 more than Lee in the end. If another $225 was given to Lee, the amount that each had in the end would be the same.
15 u + 45 = 3 u + 225
15 u - 3 u = 225 - 45
12 u = 180
1 u = 180 ÷ 12 = 15
Savings that Luis had at first
= 20 u + 60
= 20 x 15 + 60
= 300 + 60
= $360
Answer(s): $360