10% of Tim's savings was $42 more than 30% of Billy's savings. After Tim spent
13 of his savings and Billy spent 40% of his savings, Billy had $448 less than Tim. How much was Billy's saving at first?
|
Billy |
Tim |
Before |
10 u |
30 u + 420 |
Change |
- 4 u |
- 10 u - 140 |
After |
6 u |
20 u + 280 |
Comparing Billy and Tim in the end |
|
448 more |
10% =
10100 =
110 30% =
30100 =
310 110 Tim =
310 Billy + 42
Make the numerators the same. LCM of 1 and 3 is 3.
1x310x3 Tim =
3x110x1 Billy + 42
330 Tim =
310 Billy + 42
Simplify the fractions.
130 Tim =
110 Billy + 14
Let
110 Billy be
1 u.
Billy's savings at first = 10 u
130 Tim =
110 Billy + 14
Let
130 Tim be
1 u + 14.
Tim's savings at first
= 30 x (1 u + 14)
= 30 u + 420
Savings that Billy spent
= 40% x 10 u
=
40100 x 10 u
= 4 u
Savings that Tim spent
=
13 x (30 u + 420)
= 10 u + 140
Billy had $448 less than Tim in the end. If another $448 was given to Billy, the amount that each had in the end would be the same.
20 u + 280 = 6 u + 448
20 u - 6 u = 448 - 280
14 u = 168
1 u = 168 ÷ 14 = 12
Savings that Billy had at first
= 10 u
= 10 x 12
= $120
Answer(s): $120