10% of Henry's savings was $40 more than 40% of Liam's savings. After Henry spent
12 of his savings and Liam spent 40% of his savings, Henry had $291 more than Liam. How much was Henry's saving at first?
|
Liam |
Henry |
Before |
5 u |
20 u + 400 |
Change |
- 2 u |
- 10 u - 200 |
After |
3 u |
10 u + 200 |
Comparing Liam and Henry in the end |
|
291 more |
10% =
10100 =
110 40% =
40100 =
25 110 Henry =
25 Liam + 40
Make the numerators the same. LCM of 1 and 2 is 2.
1x210x2 Henry =
2x15x1 Liam + 40
220 Henry =
25 Liam + 40
Simplify the fractions.
120 Henry =
15 Liam + 20
Let
15 Liam be
1 u.
Liam's savings at first = 5 u
120 Henry =
15 Liam + 20
Let
120 Henry be
1 u + 20.
Henry's savings at first
= 20 x (1 u + 20)
= 20 u + 400
Savings that Liam spent
= 40% x 5 u
=
40100 x 5 u
= 2 u
Savings that Henry spent
=
12 x (20 u + 400)
= 10 u + 200
Henry had $291 more than Liam in the end. If another $291 was given to Liam, the amount that each had in the end would be the same.
10 u + 200 = 3 u + 291
10 u - 3 u = 291 - 200
7 u = 91
1 u = 91 ÷ 7 = 13
Savings that Henry had at first
= 20 u + 400
= 20 x 13 + 400
= 260 + 400
= $660
Answer(s): $660