10% of Dylan's savings was $51 more than 30% of Fred's savings. After Dylan spent
23 of his savings and Fred spent 40% of his savings, Fred had $246 less than Dylan. How much was Fred's saving at first?
|
Fred |
Dylan |
Before |
10 u |
30 u + 510 |
Change |
- 4 u |
- 20 u - 340 |
After |
6 u |
10 u + 170 |
Comparing Fred and Dylan in the end |
|
246 more |
10% =
10100 =
110 30% =
30100 =
310 110 Dylan =
310 Fred + 51
Make the numerators the same. LCM of 1 and 3 is 3.
1x310x3 Dylan =
3x110x1 Fred + 51
330 Dylan =
310 Fred + 51
Simplify the fractions.
130 Dylan =
110 Fred + 17
Let
110 Fred be
1 u.
Fred's savings at first = 10 u
130 Dylan =
110 Fred + 17
Let
130 Dylan be
1 u + 17.
Dylan's savings at first
= 30 x (1 u + 17)
= 30 u + 510
Savings that Fred spent
= 40% x 10 u
=
40100 x 10 u
= 4 u
Savings that Dylan spent
=
23 x (30 u + 510)
= 20 u + 340
Fred had $246 less than Dylan in the end. If another $246 was given to Fred, the amount that each had in the end would be the same.
10 u + 170 = 6 u + 246
10 u - 6 u = 246 - 170
4 u = 76
1 u = 76 ÷ 4 = 19
Savings that Fred had at first
= 10 u
= 10 x 19
= $190
Answer(s): $190