10% of Tim's savings was $15 more than 30% of David's savings. After Tim spent
13 of his savings and David spent 40% of his savings, David had $282 less than Tim. How much was David's saving at first?
|
David |
Tim |
Before |
10 u |
30 u + 150 |
Change |
- 4 u |
- 10 u - 50 |
After |
6 u |
20 u + 100 |
Comparing David and Tim in the end |
|
282 more |
10% =
10100 =
110 30% =
30100 =
310 110 Tim =
310 David + 15
Make the numerators the same. LCM of 1 and 3 is 3.
1x310x3 Tim =
3x110x1 David + 15
330 Tim =
310 David + 15
Simplify the fractions.
130 Tim =
110 David + 5
Let
110 David be
1 u.
David's savings at first = 10 u
130 Tim =
110 David + 5
Let
130 Tim be
1 u + 5.
Tim's savings at first
= 30 x (1 u + 5)
= 30 u + 150
Savings that David spent
= 40% x 10 u
=
40100 x 10 u
= 4 u
Savings that Tim spent
=
13 x (30 u + 150)
= 10 u + 50
David had $282 less than Tim in the end. If another $282 was given to David, the amount that each had in the end would be the same.
20 u + 100 = 6 u + 282
20 u - 6 u = 282 - 100
14 u = 182
1 u = 182 ÷ 14 = 13
Savings that David had at first
= 10 u
= 10 x 13
= $130
Answer(s): $130