20% of Liam's savings was $26 more than 40% of Jack's savings. After Liam spent
12 of his savings and Jack spent 40% of his savings, Liam had $85 more than Jack. How much was Liam's saving at first?
|
Jack |
Liam |
Before |
5 u |
10 u + 130 |
Change |
- 2 u |
- 5 u - 65 |
After |
3 u |
5 u + 65 |
Comparing Jack and Liam in the end |
|
85 more |
20% =
20100 =
15 40% =
40100 =
25 15 Liam =
25 Jack + 26
Make the numerators the same. LCM of 1 and 2 is 2.
1x25x2 Liam =
2x15x1 Jack + 26
210 Liam =
25 Jack + 26
Simplify the fractions.
110 Liam =
15 Jack + 13
Let
15 Jack be
1 u.
Jack's savings at first = 5 u
110 Liam =
15 Jack + 13
Let
110 Liam be
1 u + 13.
Liam's savings at first
= 10 x (1 u + 13)
= 10 u + 130
Savings that Jack spent
= 40% x 5 u
=
40100 x 5 u
= 2 u
Savings that Liam spent
=
12 x (10 u + 130)
= 5 u + 65
Liam had $85 more than Jack in the end. If another $85 was given to Jack, the amount that each had in the end would be the same.
5 u + 65 = 3 u + 85
5 u - 3 u = 85 - 65
2 u = 20
1 u = 20 ÷ 2 = 10
Savings that Liam had at first
= 10 u + 130
= 10 x 10 + 130
= 100 + 130
= $230
Answer(s): $230