10% of Elijah's savings was $54 more than 30% of Sean's savings. After Elijah spent
13 of his savings and Sean spent 40% of his savings, Elijah had $584 more than Sean. How much was Elijah's saving at first?
|
Sean |
Elijah |
Before |
10 u |
30 u + 540 |
Change |
- 4 u |
- 10 u - 180 |
After |
6 u |
20 u + 360 |
Comparing Sean and Elijah in the end |
|
584 more |
10% =
10100 =
110 30% =
30100 =
310 110 Elijah =
310 Sean + 54
Make the numerators the same. LCM of 1 and 3 is 3.
1x310x3 Elijah =
3x110x1 Sean + 54
330 Elijah =
310 Sean + 54
Simplify the fractions.
130 Elijah =
110 Sean + 18
Let
110 Sean be
1 u.
Sean's savings at first = 10 u
130 Elijah =
110 Sean + 18
Let
130 Elijah be
1 u + 18.
Elijah's savings at first
= 30 x (1 u + 18)
= 30 u + 540
Savings that Sean spent
= 40% x 10 u
=
40100 x 10 u
= 4 u
Savings that Elijah spent
=
13 x (30 u + 540)
= 10 u + 180
Elijah had $584 more than Sean in the end. If another $584 was given to Sean, the amount that each had in the end would be the same.
20 u + 360 = 6 u + 584
20 u - 6 u = 584 - 360
14 u = 224
1 u = 224 ÷ 14 = 16
Savings that Elijah had at first
= 30 u + 540
= 30 x 16 + 540
= 480 + 540
= $1020
Answer(s): $1020