10% of Ryan's savings was $40 more than 40% of Riordan's savings. After Ryan spent
15 of his savings and Riordan spent 40% of his savings, Riordan had $554 less than Ryan. How much was Riordan's saving at first?
|
Riordan |
Ryan |
Before |
5 u |
20 u + 400 |
Change |
- 2 u |
- 4 u - 80 |
After |
3 u |
16 u + 320 |
Comparing Riordan and Ryan in the end |
|
554 more |
10% =
10100 =
110 40% =
40100 =
25 110 Ryan =
25 Riordan + 40
Make the numerators the same. LCM of 1 and 2 is 2.
1x210x2 Ryan =
2x15x1 Riordan + 40
220 Ryan =
25 Riordan + 40
Simplify the fractions.
120 Ryan =
15 Riordan + 20
Let
15 Riordan be
1 u.
Riordan's savings at first = 5 u
120 Ryan =
15 Riordan + 20
Let
120 Ryan be
1 u + 20.
Ryan's savings at first
= 20 x (1 u + 20)
= 20 u + 400
Savings that Riordan spent
= 40% x 5 u
=
40100 x 5 u
= 2 u
Savings that Ryan spent
=
15 x (20 u + 400)
= 4 u + 80
Riordan had $554 less than Ryan in the end. If another $554 was given to Riordan, the amount that each had in the end would be the same.
16 u + 320 = 3 u + 554
16 u - 3 u = 554 - 320
13 u = 234
1 u = 234 ÷ 13 = 18
Savings that Riordan had at first
= 5 u
= 5 x 18
= $90
Answer(s): $90