10% of Dylan's savings was $27 more than 30% of Julian's savings. After Dylan spent
23 of his savings and Julian spent 40% of his savings, Dylan had $122 more than Julian. How much was Dylan's saving at first?
|
Julian |
Dylan |
Before |
10 u |
30 u + 270 |
Change |
- 4 u |
- 20 u - 180 |
After |
6 u |
10 u + 90 |
Comparing Julian and Dylan in the end |
|
122 more |
10% =
10100 =
110 30% =
30100 =
310 110 Dylan =
310 Julian + 27
Make the numerators the same. LCM of 1 and 3 is 3.
1x310x3 Dylan =
3x110x1 Julian + 27
330 Dylan =
310 Julian + 27
Simplify the fractions.
130 Dylan =
110 Julian + 9
Let
110 Julian be
1 u.
Julian's savings at first = 10 u
130 Dylan =
110 Julian + 9
Let
130 Dylan be
1 u + 9.
Dylan's savings at first
= 30 x (1 u + 9)
= 30 u + 270
Savings that Julian spent
= 40% x 10 u
=
40100 x 10 u
= 4 u
Savings that Dylan spent
=
23 x (30 u + 270)
= 20 u + 180
Dylan had $122 more than Julian in the end. If another $122 was given to Julian, the amount that each had in the end would be the same.
10 u + 90 = 6 u + 122
10 u - 6 u = 122 - 90
4 u = 32
1 u = 32 ÷ 4 = 8
Savings that Dylan had at first
= 30 u + 270
= 30 x 8 + 270
= 240 + 270
= $510
Answer(s): $510