10% of Rael's savings was $27 more than 30% of Howard's savings. After Rael spent
25 of his savings and Howard spent 40% of his savings, Rael had $330 more than Howard. How much was Rael's saving at first?
|
Howard |
Rael |
Before |
10 u |
30 u + 270 |
Change |
- 4 u |
- 12 u - 108 |
After |
6 u |
18 u + 162 |
Comparing Howard and Rael in the end |
|
330 more |
10% =
10100 =
110 30% =
30100 =
310 110 Rael =
310 Howard + 27
Make the numerators the same. LCM of 1 and 3 is 3.
1x310x3 Rael =
3x110x1 Howard + 27
330 Rael =
310 Howard + 27
Simplify the fractions.
130 Rael =
110 Howard + 9
Let
110 Howard be
1 u.
Howard's savings at first = 10 u
130 Rael =
110 Howard + 9
Let
130 Rael be
1 u + 9.
Rael's savings at first
= 30 x (1 u + 9)
= 30 u + 270
Savings that Howard spent
= 40% x 10 u
=
40100 x 10 u
= 4 u
Savings that Rael spent
=
25 x (30 u + 270)
= 12 u + 108
Rael had $330 more than Howard in the end. If another $330 was given to Howard, the amount that each had in the end would be the same.
18 u + 162 = 6 u + 330
18 u - 6 u = 330 - 162
12 u = 168
1 u = 168 ÷ 12 = 14
Savings that Rael had at first
= 30 u + 270
= 30 x 14 + 270
= 420 + 270
= $690
Answer(s): $690