10% of Perry's savings was $9 more than 30% of Peter's savings. After Perry spent
15 of his savings and Peter spent 40% of his savings, Perry had $216 more than Peter. How much was Perry's saving at first?
|
Peter |
Perry |
Before |
10 u |
30 u + 90 |
Change |
- 4 u |
- 6 u - 18 |
After |
6 u |
24 u + 72 |
Comparing Peter and Perry in the end |
|
216 more |
10% =
10100 =
110 30% =
30100 =
310 110 Perry =
310 Peter + 9
Make the numerators the same. LCM of 1 and 3 is 3.
1x310x3 Perry =
3x110x1 Peter + 9
330 Perry =
310 Peter + 9
Simplify the fractions.
130 Perry =
110 Peter + 3
Let
110 Peter be
1 u.
Peter's savings at first = 10 u
130 Perry =
110 Peter + 3
Let
130 Perry be
1 u + 3.
Perry's savings at first
= 30 x (1 u + 3)
= 30 u + 90
Savings that Peter spent
= 40% x 10 u
=
40100 x 10 u
= 4 u
Savings that Perry spent
=
15 x (30 u + 90)
= 6 u + 18
Perry had $216 more than Peter in the end. If another $216 was given to Peter, the amount that each had in the end would be the same.
24 u + 72 = 6 u + 216
24 u - 6 u = 216 - 72
18 u = 144
1 u = 144 ÷ 18 = 8
Savings that Perry had at first
= 30 u + 90
= 30 x 8 + 90
= 240 + 90
= $330
Answer(s): $330