10% of Eric's savings was $8 more than 40% of Cody's savings. After Eric spent
12 of his savings and Cody spent 40% of his savings, Eric had $159 more than Cody. How much was Eric's saving at first?
|
Cody |
Eric |
Before |
5 u |
20 u + 80 |
Change |
- 2 u |
- 10 u - 40 |
After |
3 u |
10 u + 40 |
Comparing Cody and Eric in the end |
|
159 more |
10% =
10100 =
110 40% =
40100 =
25 110 Eric =
25 Cody + 8
Make the numerators the same. LCM of 1 and 2 is 2.
1x210x2 Eric =
2x15x1 Cody + 8
220 Eric =
25 Cody + 8
Simplify the fractions.
120 Eric =
15 Cody + 4
Let
15 Cody be
1 u.
Cody's savings at first = 5 u
120 Eric =
15 Cody + 4
Let
120 Eric be
1 u + 4.
Eric's savings at first
= 20 x (1 u + 4)
= 20 u + 80
Savings that Cody spent
= 40% x 5 u
=
40100 x 5 u
= 2 u
Savings that Eric spent
=
12 x (20 u + 80)
= 10 u + 40
Eric had $159 more than Cody in the end. If another $159 was given to Cody, the amount that each had in the end would be the same.
10 u + 40 = 3 u + 159
10 u - 3 u = 159 - 40
7 u = 119
1 u = 119 ÷ 7 = 17
Savings that Eric had at first
= 20 u + 80
= 20 x 17 + 80
= 340 + 80
= $420
Answer(s): $420