25% of Peter's savings was $6 more than 30% of Neave's savings. After Peter spent
14 of his savings and Neave spent 40% of his savings, Neave had $30 less than Peter. How much was Neave's saving at first?
|
Neave |
Peter |
Before |
10 u |
12 u + 24 |
Change |
- 4 u |
- 3 u - 6 |
After |
6 u |
9 u + 18 |
Comparing Neave and Peter in the end |
|
30 more |
25% =
25100 =
14 30% =
30100 =
310 14 Peter =
310 Neave + 6
Make the numerators the same. LCM of 1 and 3 is 3.
1x34x3 Peter =
3x110x1 Neave + 6
312 Peter =
310 Neave + 6
Simplify the fractions.
112 Peter =
110 Neave + 2
Let
110 Neave be
1 u.
Neave's savings at first = 10 u
112 Peter =
110 Neave + 2
Let
112 Peter be
1 u + 2.
Peter's savings at first
= 12 x (1 u + 2)
= 12 u + 24
Savings that Neave spent
= 40% x 10 u
=
40100 x 10 u
= 4 u
Savings that Peter spent
=
14 x (12 u + 24)
= 3 u + 6
Neave had $30 less than Peter in the end. If another $30 was given to Neave, the amount that each had in the end would be the same.
9 u + 18 = 6 u + 30
9 u - 6 u = 30 - 18
3 u = 12
1 u = 12 ÷ 3 = 4
Savings that Neave had at first
= 10 u
= 10 x 4
= $40
Answer(s): $40