10% of Brandon's savings was $32 more than 40% of Michael's savings. After Brandon spent
14 of his savings and Michael spent 40% of his savings, Brandon had $288 more than Michael. How much was Brandon's saving at first?
|
Michael |
Brandon |
Before |
5 u |
20 u + 320 |
Change |
- 2 u |
- 5 u - 80 |
After |
3 u |
15 u + 240 |
Comparing Michael and Brandon in the end |
|
288 more |
10% =
10100 =
110 40% =
40100 =
25 110 Brandon =
25 Michael + 32
Make the numerators the same. LCM of 1 and 2 is 2.
1x210x2 Brandon =
2x15x1 Michael + 32
220 Brandon =
25 Michael + 32
Simplify the fractions.
120 Brandon =
15 Michael + 16
Let
15 Michael be
1 u.
Michael's savings at first = 5 u
120 Brandon =
15 Michael + 16
Let
120 Brandon be
1 u + 16.
Brandon's savings at first
= 20 x (1 u + 16)
= 20 u + 320
Savings that Michael spent
= 40% x 5 u
=
40100 x 5 u
= 2 u
Savings that Brandon spent
=
14 x (20 u + 320)
= 5 u + 80
Brandon had $288 more than Michael in the end. If another $288 was given to Michael, the amount that each had in the end would be the same.
15 u + 240 = 3 u + 288
15 u - 3 u = 288 - 240
12 u = 48
1 u = 48 ÷ 12 = 4
Savings that Brandon had at first
= 20 u + 320
= 20 x 4 + 320
= 80 + 320
= $400
Answer(s): $400