10% of Zane's savings was $12 more than 40% of Cody's savings. After Zane spent
12 of his savings and Cody spent 40% of his savings, Cody had $165 less than Zane. How much was Cody's saving at first?
|
Cody |
Zane |
Before |
5 u |
20 u + 120 |
Change |
- 2 u |
- 10 u - 60 |
After |
3 u |
10 u + 60 |
Comparing Cody and Zane in the end |
|
165 more |
10% =
10100 =
110 40% =
40100 =
25 110 Zane =
25 Cody + 12
Make the numerators the same. LCM of 1 and 2 is 2.
1x210x2 Zane =
2x15x1 Cody + 12
220 Zane =
25 Cody + 12
Simplify the fractions.
120 Zane =
15 Cody + 6
Let
15 Cody be
1 u.
Cody's savings at first = 5 u
120 Zane =
15 Cody + 6
Let
120 Zane be
1 u + 6.
Zane's savings at first
= 20 x (1 u + 6)
= 20 u + 120
Savings that Cody spent
= 40% x 5 u
=
40100 x 5 u
= 2 u
Savings that Zane spent
=
12 x (20 u + 120)
= 10 u + 60
Cody had $165 less than Zane in the end. If another $165 was given to Cody, the amount that each had in the end would be the same.
10 u + 60 = 3 u + 165
10 u - 3 u = 165 - 60
7 u = 105
1 u = 105 ÷ 7 = 15
Savings that Cody had at first
= 5 u
= 5 x 15
= $75
Answer(s): $75