10% of Sean's savings was $4 more than 40% of George's savings. After Sean spent
12 of his savings and George spent 40% of his savings, George had $48 less than Sean. How much was George's saving at first?
|
George |
Sean |
Before |
5 u |
20 u + 40 |
Change |
- 2 u |
- 10 u - 20 |
After |
3 u |
10 u + 20 |
Comparing George and Sean in the end |
|
48 more |
10% =
10100 =
110 40% =
40100 =
25 110 Sean =
25 George + 4
Make the numerators the same. LCM of 1 and 2 is 2.
1x210x2 Sean =
2x15x1 George + 4
220 Sean =
25 George + 4
Simplify the fractions.
120 Sean =
15 George + 2
Let
15 George be
1 u.
George's savings at first = 5 u
120 Sean =
15 George + 2
Let
120 Sean be
1 u + 2.
Sean's savings at first
= 20 x (1 u + 2)
= 20 u + 40
Savings that George spent
= 40% x 5 u
=
40100 x 5 u
= 2 u
Savings that Sean spent
=
12 x (20 u + 40)
= 10 u + 20
George had $48 less than Sean in the end. If another $48 was given to George, the amount that each had in the end would be the same.
10 u + 20 = 3 u + 48
10 u - 3 u = 48 - 20
7 u = 28
1 u = 28 ÷ 7 = 4
Savings that George had at first
= 5 u
= 5 x 4
= $20
Answer(s): $20