10% of Charlie's savings was $36 more than 30% of Simon's savings. After Charlie spent
12 of his savings and Simon spent 40% of his savings, Simon had $198 less than Charlie. How much was Simon's saving at first?
|
Simon |
Charlie |
Before |
10 u |
30 u + 360 |
Change |
- 4 u |
- 15 u - 180 |
After |
6 u |
15 u + 180 |
Comparing Simon and Charlie in the end |
|
198 more |
10% =
10100 =
110 30% =
30100 =
310 110 Charlie =
310 Simon + 36
Make the numerators the same. LCM of 1 and 3 is 3.
1x310x3 Charlie =
3x110x1 Simon + 36
330 Charlie =
310 Simon + 36
Simplify the fractions.
130 Charlie =
110 Simon + 12
Let
110 Simon be
1 u.
Simon's savings at first = 10 u
130 Charlie =
110 Simon + 12
Let
130 Charlie be
1 u + 12.
Charlie's savings at first
= 30 x (1 u + 12)
= 30 u + 360
Savings that Simon spent
= 40% x 10 u
=
40100 x 10 u
= 4 u
Savings that Charlie spent
=
12 x (30 u + 360)
= 15 u + 180
Simon had $198 less than Charlie in the end. If another $198 was given to Simon, the amount that each had in the end would be the same.
15 u + 180 = 6 u + 198
15 u - 6 u = 198 - 180
9 u = 18
1 u = 18 ÷ 9 = 2
Savings that Simon had at first
= 10 u
= 10 x 2
= $20
Answer(s): $20