On a shelf, there were 56 cardigans and jackets. Ian spilt tea on the shelf and stained 50% of the jackets and 10% of the cardigans. If 48 cardigans and jackets were still clean, how many clean jackets were there?
| |
Cardigans |
Jackets |
Total |
| Stained |
1 u |
1 p |
8 |
| Clean |
9 u |
1 p |
48 |
| Total |
10 u |
2 p |
56 |
50% =
50100 =
12 10% =
10100 =
110 Number of stained clothes
= 56 - 48
= 8
9 u + 1 p = 48
1 p = 48 - 9 u --- (1)
1 u + 1 p = 8
1 p = 8 - 1 u --- (2)
(2) - (1)
8 - 1 u = 48 - 9 u
9 u - 1 u = 48 - 8
8 u = 40
1 u = 40 ÷ 8 = 5
Number of clean jackets is the same as the number of stained jackets.
Number of clean jackets
= 8 - 1 u
= 8 - 5
= 3
Answer(s): 3
