On a shelf, there were 88 sweaters and jackets. Daniel spilt hot milk on the shelf and stained 50% of the jackets and 10% of the sweaters. If 72 sweaters and jackets were still clean, how many stained jackets were there?
| |
Sweaters |
Jackets |
Total |
| Stained |
1 u |
1 p |
16 |
| Clean |
9 u |
1 p |
72 |
| Total |
10 u |
2 p |
88 |
50% =
50100 =
12 10% =
10100 =
110 Number of stained clothes
= 88 - 72
= 16
9 u + 1 p = 72
1 p = 72 - 9 u --- (1)
1 u + 1 p = 16
1 p = 16 - 1 u --- (2)
(2) - (1)
16 - 1 u = 72 - 9 u
9 u - 1 u = 72 - 16
8 u = 56
1 u = 56 ÷ 8 = 7
Number of stained jackets
= 16 - 1 u
= 16 - 7
= 9
Answer(s): 9
