Eric has 40% more coins than Bryan. Paul has 80% the number of coins Eric has.
- What is the ratio of the number of Bryan's coins to the number of Paul's coins?
- If the total number of coins of Eric's and Paul's is 304 more than Bryan's, how many coins does Eric have?
Eric |
Bryan |
Paul |
7x5 |
5x5 |
|
5x7 |
|
4x7 |
35 u |
25 u |
28 u |
100% + 40% = 140%
140% =
140100 =
75 Eric's coins : Bryan's coins = 35 : 25
80% =
80100 =
45 Paul's coins : Eric's coins = 28 : 35
Bryan's coins: Paul's coins = 25 : 28 (a)
Eric's coins + Paul's coins = 35 u + 28 u = 63 u
Bryan's coins = 25 u
63 u - 25 u = 304
38 u = 304
1 u = 304 ÷ 38 = 8
Number of Eric's coins
= 35 u
= 35 x 8
= 280 (b)
Answers: (a) 25 : 28; (b) 280