Ryan has 40% more coins than Eric. Ken has 80% the number of coins Ryan has.
- What is the ratio of the number of Eric's coins to the number of Ken's coins?
- If the total number of coins of Ryan's and Ken's is 342 more than Eric's, how many coins does Ryan have?
Ryan |
Eric |
Ken |
7x5 |
5x5 |
|
5x7 |
|
4x7 |
35 u |
25 u |
28 u |
100% + 40% = 140%
140% =
140100 =
75 Ryan's coins : Eric's coins = 35 : 25
80% =
80100 =
45 Ken's coins : Ryan's coins = 28 : 35
Eric's coins: Ken's coins = 25 : 28 (a)
Ryan's coins + Ken's coins = 35 u + 28 u = 63 u
Eric's coins = 25 u
63 u - 25 u = 342
38 u = 342
1 u = 342 ÷ 38 = 9
Number of Ryan's coins
= 35 u
= 35 x 9
= 315 (b)
Answers: (a) 25 : 28; (b) 315