Ian has 40% more buttons than Albert. Jenson has 80% the number of buttons Ian has.
- What is the ratio of the number of Albert's buttons to the number of Jenson's buttons?
- If the total number of buttons of Ian's and Jenson's is 342 more than Albert's, how many buttons does Ian have?
Ian |
Albert |
Jenson |
7x5 |
5x5 |
|
5x7 |
|
4x7 |
35 u |
25 u |
28 u |
100% + 40% = 140%
140% =
140100 =
75 Ian's buttons : Albert's buttons = 35 : 25
80% =
80100 =
45 Jenson's buttons : Ian's buttons = 28 : 35
Albert's buttons: Jenson's buttons = 25 : 28 (a)
Ian's buttons + Jenson's buttons = 35 u + 28 u = 63 u
Albert's buttons = 25 u
63 u - 25 u = 342
38 u = 342
1 u = 342 ÷ 38 = 9
Number of Ian's buttons
= 35 u
= 35 x 9
= 315 (b)
Answers: (a) 25 : 28; (b) 315