Luis has 40% more coins than Oliver. Neave has 80% the number of coins Luis has.
- What is the ratio of the number of Oliver's coins to the number of Neave's coins?
- If the total number of coins of Luis's and Neave's is 304 more than Oliver's, how many coins does Luis have?
Luis |
Oliver |
Neave |
7x5 |
5x5 |
|
5x7 |
|
4x7 |
35 u |
25 u |
28 u |
100% + 40% = 140%
140% =
140100 =
75 Luis's coins : Oliver's coins = 35 : 25
80% =
80100 =
45 Neave's coins : Luis's coins = 28 : 35
Oliver's coins: Neave's coins = 25 : 28 (a)
Luis's coins + Neave's coins = 35 u + 28 u = 63 u
Oliver's coins = 25 u
63 u - 25 u = 304
38 u = 304
1 u = 304 ÷ 38 = 8
Number of Luis's coins
= 35 u
= 35 x 8
= 280 (b)
Answers: (a) 25 : 28; (b) 280