John has 40% more coins than Gabriel. Tommy has 80% the number of coins John has.
- What is the ratio of the number of Gabriel's coins to the number of Tommy's coins?
- If the total number of coins of John's and Tommy's is 342 more than Gabriel's, how many coins does John have?
John |
Gabriel |
Tommy |
7x5 |
5x5 |
|
5x7 |
|
4x7 |
35 u |
25 u |
28 u |
100% + 40% = 140%
140% =
140100 =
75 John's coins : Gabriel's coins = 35 : 25
80% =
80100 =
45 Tommy's coins : John's coins = 28 : 35
Gabriel's coins: Tommy's coins = 25 : 28 (a)
John's coins + Tommy's coins = 35 u + 28 u = 63 u
Gabriel's coins = 25 u
63 u - 25 u = 342
38 u = 342
1 u = 342 ÷ 38 = 9
Number of John's coins
= 35 u
= 35 x 9
= 315 (b)
Answers: (a) 25 : 28; (b) 315