110 of the guests at a tourist attraction were men. 70% of the remaining guests were women and the rest were children. The number of women was 182 more than the total number of men and children. After some women left the tourist attraction, 50% of the guests that remained were women. How many women left the tourist attraction?
Men |
Children |
Women |
Total |
1x10 |
9x10 |
10x10 |
|
3x9 |
7x9 |
|
10 |
27 |
63 |
100 |
|
Men and children |
Women |
Before |
37x1 = 37 u |
63x1 = 63 u |
Change |
|
- 26 u |
After
|
1x37 = 37 u |
1x37 = 37 u |
70% =
70100 =
710 Children : Women = 3 : 7
The total number of children and women at first is repeated. Make the total number of children at first the same. LCM of 9 and 10 is 90.
50% =
50100 =
12 When some women left, the total number of men and children remains unchanged. Make the total number of men and children the same. LCM of 37 and 1 is 37.
The number of women was 182 more than the total number of men and children at first.
Number of more women than the total number of men and children at first
= 63 u - 37 u
= 26 u
26 u = 182
1 u = 182 ÷ 26 = 7
Number of women who left the tourist attraction
= 63 u - 37 u
= 26 u
= 26 x 7
= 182
Answer(s): 182