110 of the visitors at a safari park were men. 80% of the remaining visitors were women and the rest were children. The number of women was 418 more than the total number of men and children. After some women left the safari park, 60% of the visitors that remained were women. How many women left the safari park?
Men |
Children |
Women |
Total |
1x5 |
9x5 |
10x5 |
|
1x9 |
4x9 |
|
5 |
9 |
36 |
50 |
|
Men and children |
Women |
Before |
14x1 = 14 u |
36x1 = 36 u |
Change |
|
- 15 u |
After
|
2x7 = 14 u |
3x7 = 21 u |
80% =
80100 =
45 Children : Women = 1 : 4
The total number of children and women at first is repeated. Make the total number of children at first the same. LCM of 9 and 5 is 45.
60% =
60100 =
35 When some women left, the total number of men and children remains unchanged. Make the total number of men and children the same. LCM of 14 and 2 is 14.
The number of women was 418 more than the total number of men and children at first.
Number of more women than the total number of men and children at first
= 36 u - 14 u
= 22 u
22 u = 418
1 u = 418 ÷ 22 = 19
Number of women who left the safari park
= 36 u - 21 u
= 15 u
= 15 x 19
= 285
Answer(s): 285